Core Concept

Why Factor?

If A × B = 0, then either A = 0 or B = 0. This is the zero product property. Factoring rewrites the quadratic as a product of two brackets, then we set each bracket to zero.

x² + 5x + 6 = 0
(x + 2)(x + 3) = 0
x = −2 or x = −3

Method

Factoring When a = 1

For x² + bx + c, find two numbers that multiply to c and add to b.

Example: Solve x² + 7x + 12 = 0

1. Need two numbers: multiply to 12, add to 7
2. Pairs that multiply to 12: (1,12), (2,6), (3,4)
3. 3 + 4 = 7 ✓
4. Factor: (x + 3)(x + 4) = 0
5. x = −3 or x = −4

Negative Numbers

Factoring with Negatives

Example: Solve x² − x − 12 = 0

1. Need: multiply to −12, add to −1
2. Try: (−4)(3) = −12, and −4 + 3 = −1 ✓
3. Factor: (x − 4)(x + 3) = 0
4. x = 4 or x = −3

Special Cases

Difference of Squares

When you have x² − k² (a perfect square minus a perfect square), it always factors as:

x² − k² = (x + k)(x − k)

Examples:

x² − 25 = (x + 5)(x − 5) → x = ±5
x² − 49 = (x + 7)(x − 7) → x = ±7
4x² − 9 = (2x + 3)(2x − 3) → x = ±3/2

Advanced

Factoring When a ≠ 1

Example: Factor 2x² + 7x + 3

1. Multiply a × c: 2 × 3 = 6
2. Find two numbers: multiply to 6, add to 7 → (1, 6)
3. Rewrite middle: 2x² + 1x + 6x + 3
4. Group: x(2x + 1) + 3(2x + 1)
5. Factor: (x + 3)(2x + 1)
6. x = −3 or x = −1/2

Watch Out

Common Mistakes

Your Turn

Try It Yourself

Q1. Solve x² + 6x + 8 = 0 by factoring.

Show Answer
(x + 2)(x + 4) = 0 → x = −2 or x = −4

Q2. Factor and solve x² − 16 = 0.

Show Answer
(x + 4)(x − 4) = 0 → x = ±4

Q3. Solve x² − 3x − 10 = 0.

Show Answer
Need: multiply to −10, add to −3 → (−5)(2)
(x − 5)(x + 2) = 0 → x = 5 or x = −2

Key Takeaways

1-Minute Summary

← Lesson 1: Intro to Quadratics Next: Completing the Square →